2.4 Angles between vectors and Orthogonality

In addition to enabling the definition of lengths of vectors, as well as the distance between two vectors, inner products also capture the geometry of a vector space by defining the angle $\omega$ between two vectors.

Assume $x \ne 0, y \ne 0$, then

$-1 \le  \frac{<x,y> }{\left \| x \right \|\left \| y\right \|}$ $\le 1$

therefore there exist a unique $\omega \in [0,\pi]$ with

$cos \omega=  \frac{<x,y> }{\left \| x \right \|\left \| y\right \|}$

The number $\omega$ is the angle between the vectors $x$ and $y$. Intuitively, the angle between two vectors tells us how similar their orientations are. For example, using the dot product, the angle between $x$ and $y = 4x$, i.e., y is a scaled version of x, is 0: Their orientation is the same.

Example ( university question)

Lets consider the angle between $x=[1,1]^T \in \mathbb{R}^2$ and $y=[1,2]^T \in \mathbb{R}^2$.If we use dot product as the inner product

$cos \omega=\frac{<x,y>}{\sqrt{<x,x><y,y>}}=\frac{x^Ty}{\sqrt{x^Txy^Ty}}=\frac{3}{\sqrt{10}}$

and the angle between the two vectors is $arccos(\frac{3}{\sqrt{10}}) \approx 0.32 rad$, which corresponds to about $18^{\circ}$.

# calculating angle between vectors

from math import sqrt

import numpy as np

# define data

x =np.array([1,1])

y =np.array([1,2])

print("x")

print(x)

print("y")

print(y)

cosw = x.dot(y)/(sqrt(x.dot(x)*y.dot(y)))

print("angle between vectors in radiance")

print(np.arccos(cosw))

print("angle between vectors in degrees")

print(np.arccos(cosw)*180.0/np.pi)

O/P

x 

[1 1] 

y 

[1 2] 

angle between vectors in radiance 

0.3217505543966423 

angle between vectors in degrees 

18.434948822922017

Orthogonality

Two vectors $x$ and $y$ are orthogonal if and only if $<x,y>=0$, and we write $x \perp y$. If additionally $\left \| x \right \| = 1 = \left \| y \right \|$, i.e., the vectors are unit vectors, then $x$ and $y$ are orthonormal.

An implication of this definition is that the 0-vector is orthogonal to every vector in the vector space.

Note: vectors that are orthogonal with respect to one inner product do not have to be orthogonal with respect to different inner product.

Example:University question

Are the vectors $x = [2, 5 ,1]^𝑇$ and $y = [9, −3 ,6]^𝑇$ orthogonal?. Justify your answer.

Their  dot product is $2*9 + 5* -3 + 1*6=18-15+6=9$, which is not equal to zero.

So the vectors are not orthogonal.

The angle between them is $(\theta)=arccos(9/\sqrt{30}.\sqrt{126})$, which is not 90 degrees.

Example:University question

Determine whether the vectors
$a=\begin{bmatrix} 3\\ 0\\ -2 \end{bmatrix} b=\begin{bmatrix} 2\\ 0\\ 3 \end{bmatrix}$ are orthogonal or not

The dot product $a.b=6+0-6=0$. Hence the vectors are orthogonal